Question

Допоможіть. зробити Алгебру дам 40 балів.
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Answer 1

1.

1) (x+3)² = x² + 2x * 3 + 3² = x² + 6x + 9

2) (4-y)² = 16 - 8y + y² = y²- 8y + 16

3) (2m-5)² = (2m)² - 2 * 2m * 5 + 5² = 4m² - 20m + 25

4) (7a+6b)² = (7a)² + 2 * 7a * 6b + (6b)² = 49a² + 84ab + 36b²

2. 1) (0,2x-10y)² = (⅕x - 10y)² = ¹/²⁵x² - 4xy + 100y² або 0,04x² - 4xy + 100y²

2) (9m+⅓n)² = (9m)² + 2 * 9m * ⅓n + (⅓n)² = 81m² + 6mn + ⅑n²

3) (a²-1)² = (a²)² - 2a² * 1 + 1² = a⁴ - 2a² + 1

4) (x³+3x²)² = (x³)² + 2x³ * 3x² + (3x²) ² = x⁶ + 6x⁵ + 9x⁴

3.

1) (x+4)² - 16 = x² + 8x + 16 - 16 = x² + 8x

2) 10a - (a-5)² = 10a - (a² - 10a + 25) = 10a - a² + 10a - 25 = 20a - a² - 25 = -a² + 20a - 25

3) (3m-7n)² - (3m+7n)² = (3m-7n - (3m+7n)) * (3m -7n + 3m + 7n) = (3m - 7n - 3m - 7n) * 6m = (-14n) * 6m = -84mn

4) b(b+3) - (b-4)² = b² + 3b - (b²-8b+16) = b² + 3b - b²+8b-16 = 11b - 16

4.

1) (x-1) = (x-1)² = x² - 2x * 1 + 1² = x² - 2x + 1

2) (x+1) = (x+1)² = x² + 2x * 1 + 1² = x² + 2x + 1

3) (a+3)(a-3) = (a+3)² * (a-3)² = ((a+3)(a-3))² = (a²-3²)² = (a²- 9)² = a⁴ - 18a² + 81