Question

1)5x-27
-------- =0
   7 
2)(b^5/6)^3*4√b^3

Answer 1

5x-27
-------- =0
7 

5х-27=0*7
5х-27=0
5х=27
х=27/5=5,4

2)
$(b^{5/6} )^3*4 sqrt{b^3} = b^{5*3/6}*4 sqrt{b^3} =b^{5/2}*4 sqrt{b^3} =4 sqrt{b^3*(b^{5/2})^2} = \ 4 sqrt{b^3*b^{5*2/2}} =4 sqrt{b^3*b^{5}} =4 sqrt{b^8} =4 sqrt{(b^4)^2} =4 b^4$