Question

(3√2-1)^2+2√18 помогииииииите

Answer 1

$(3sqrt2-1)^2+2sqrt{18}=(3sqrt2)^2-2cdot3sqrt2cdot1+1^2+2sqrt{9cdot2}\\=9cdot2-6sqrt2+1+2cdotsqrt9cdotsqrt2=18-6sqrt2+1+2cdot3sqrt2\\=19-6sqrt2+6sqrt2=19$

Answer 2

$(3 sqrt{2} -1) ^{2} +2 sqrt{18}=19 \ 1) (3 sqrt{2} -1) ^{2} =(3 sqrt{2})^{2} +1^{2} -2*1*3 sqrt{2} =18+1-6 sqrt{2} = \ =19-6 sqrt{2} \ 2) 19-6 sqrt{2} +2 sqrt{18} =19-6 sqrt{2} +2 sqrt{2*9} =19-6 sqrt{2} +6 sqrt{2} =19$