Question

(4x^-2 y^3)^2 * (0,5x^2 y^-1)^3

Answer 1

$(4x^{-2}y^{3})^{2}*(0.5x^{2}y^{-1})^{3}=(8x^{-4}y^{6})*(0.125x^{6}y^{-3})= \ =8*0.125*x^{-4+6}y^{6-3}=1x^{2}y^{3}=x^{2}y^{3}$