Question

$[tex]9 x^{3}-15 x^{2} -32 x-12=0$

Answer 1

$9x^3-15x^2-32x-12=0$
$9x^3-27x^2+12x^2-36x+4x-12=0$
$9x^2(x-3)+12x(x-3)+4(x-3)=0$
$(9x^2+12x+4)(x-3)=0$
$9x^12+12x+4=0$
$(3x+2)^2=0$
$3x+2=0$
$x_1=-frac{2}{3}$
$x-3=0;x_2=3$
ответ: -2/3; 3