Question

эваюжавллат решите поалцйтса​

Answer 1

$\displaystyle\bf\\1)\\\\\frac{5a+b^{5} }{8b} -\frac{5a-7b^{5} }{8b} =\frac{5a+b^{5} -5a+7b^{5} }{8b} =\frac{8b^{5} }{8b} =b^{4} \\\\2)\\\\\frac{2x-3y}{4xy} +\frac{11y-2x }{4xy} =\frac{2x-3y+11y-2x }{4xy} =\frac{8y}{4xy} =\frac{2}{x} \\\\3)\\\\\frac{3x-y^{4} }{4y^{5} } -\frac{y^{4}+3x }{4y^{5} } =\frac{3x-y^{4} -y^{4}-3x }{4y^{5} } =\frac{-2y^{4} }{4y^{5} }=-\frac{1}{2y}$

$\displaystyle\bf\\4)\\\\\frac{a-2}{7a} +\frac{2a+5}{7a} -\frac{3-a}{7a} =\frac{a-2+2a+5-3+a}{7a}=\frac{4a}{7a} =\frac{4}{7} \\\\5)\\\\\frac{7y-5}{11y}- \frac{10y-9}{11y} +\frac{10-5y}{11y} =\frac{7y-5-10y+9+10-5y}{11y}=\\\\\\=\frac{14-8y}{11y} \\\\6)\\\\\frac{21a+2b}{6a} +\frac{21a-3b}{6a} -\frac{36a-b}{6a} =\frac{21a+2b+21a-3b-36a+b}{6a}=\\\\\\=\frac{6a}{6a}=1$