Question

а)z²x²-0,09y²
б)(x+2)²-25
в)(x-y)²-(x+y)²
г)a²+8ab+16b⁶
помогите отдаю полежние баллы​

Answer 1

$\displaystyle\bf\\1)\\\\z^{2} x^{2} -0,09y^{2} =(zx)^{2} -(0,3y)^{2} =(zx-0,3y)\cdot(zx+0,3y)\\\\\\2)\\\\(x+2)^{2} -25=(x+2)^{2} -5^{2} =(x+2-5)\cdot(x+2+5)=\\\\=(x-3)\cdot(x+7)\\\\\\3)\\\\(x-y)^{2} -(x+y)^{2} =(x-y-x-y)\cdot(x-y+x+y)=\\\\=-2y\cdot 2x=-4xy\\\\\\4)\\\\a^{2} +8ab^{3} +16b^{6}=a^{2} +2\cdot a\cdot 4b^{3} +(4b^{3} )^{2} =(a+4b^{3} )^{2} =\\\\=(a+4b^{3} )(a+4b^{3} )$