Предмет: Геометрия, автор: girlokay

НЕОБЫЧНОЕ ЗАДАНИЕ
Предположим, что земной шар охвачен по экватору обручем, длина которого превышает длину экватора на 10 метров, причем обруч везде одинаково удален от поверхности Земли. Какой размер промежутка между земной поверхностью и обручем? Смогла бы пролезть под обручем мышь?

kanmmu: Знакомая задача. Кажется, в учебнике Атанасяна была...

dnepr1: Зазор около 1,6 м.

dnepr1: 40075000 40075010 6,283185307
6378134,344 6378135,936 1,591549431

Ответы

Автор ответа: siestarjoki

1

Э - длина экватора

R=L/2п

Найдем разность радиусов обруча и Земли.

Ro-Rз =(Э+10)/2п -Э/2п =5/п ~1,59 (м)

Приложения:

siestarjoki: Все точки окружности удалены от центра на радиус. По условию все точки обруча удалены на равное расстояние от поверхности Земли, следовательно равноудалены от центра Земли. Окружности концентрические.

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