Question

4)
1
16X*+9
2-IX
- )
27
4x
Много балов
Помогите

Answer 1

$(1-\frac{16x^2+9}{24x}):(\frac{1}{4x}-\frac{1}{3})-2x=\frac{24x-(16x^2+9)}{24x}:\frac{3-4x}{12x}-2x=\frac{24x-16x^2-9}{24x}\cdot\frac{12x}{3-4x}-2x=\frac{-(16x^2-24x+9)}{2}\cdot\frac{1}{-(4x-3)}-2x=\frac{-(4x-3)^2}{2}\cdot\frac{1}{-(4x-3)}-2x=\frac{4x-3}{2}-2x=\frac{4x-3-4x}{2}=\frac{-3}{2}=-\frac{3}{2}$