Предмет: Физика, автор: amantai228

Тело объемом 2 м3 погружено в воду. Найдите архимедову силу, действующую на тело. Плотность воды 1000 кг/м3.
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Ответы

Автор ответа: max197828
10

Ответ:

20000

Объяснение:

Выталкивающая сила - сила Архимеда равна:

F_{A}=pgV

Где р - плотность жидкости, g - скорость свободного падения, V - объем тела

плотность воды 1000 кг/м3, g=10 м/с2 - постоянные значения.

F=1000*10*2 Н=20 000 Н

Ответ: F=20 000 Н.

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