Question

\frac{c+1}{3}-\frac{c+2}{6}-\frac{c+3}{2}

Answer 1

$\frac{c+1}{3}-\frac{c+2}{6}-\frac{c+3}{2}=\frac{2(c+1)-(c+2)-3(c+3)}{6}=\\\\=\frac{2c+2-c-2-3c-9}{6}=\frac{-2c-9}{6}=-\frac{1}{3}c-\frac{3}{2}$