Question

$\frac{\sqrt{15}-\sqrt{6}}{\sqrt{35}-\sqrt{14} }$
Помогите решить

Answer 1

Ответ:

Пошаговое объяснение:

$\displaystyle\\\frac{\sqrt{15}-\sqrt{6} }{\sqrt{35}-\sqrt{14}} =\frac{\sqrt{3*5}-\sqrt{2*3} }{\sqrt{7*5}-\sqrt{7*2}} =\frac{\sqrt{3} (\sqrt{5}-\sqrt{2} ) }{\sqrt{7} (\sqrt{5}-\sqrt{2} )} =\frac{\sqrt{3} }{\sqrt{7}}=\frac{\sqrt{21} }{7}$