Question

Пожалуйста, помогите.
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Answer 1

5) =(а^6*9^2/b^8)*(b^9/(9^3*a^6)= b/9

6) =(100*p^8*q^10*k^4)/ (125*p^6*q^9* k^3)= (100/125)*p²qk=4p²qk/5

Answer 2

$\displaystyle\tt5)~\Big(\frac{a^{-3}b^4}{9}\Big)^{-2} \cdot\Big(\frac{9}{a^{-2}b^3}\Big)^{-3} =\\\\\\=\frac{a^6b^{-8}}{9^{-2}} \cdot\frac{9^{-3}}{a^6b^{-9}} =\\\\\\=9^2a^6b^{-8}\cdot\frac{1}{9^3a^6b^{-9}}=\\\\\\=\frac{9^2a^6b^{-8}}{9^3a^6b^{-9}}=\frac{b}{9}$

$\displaystyle\tt6)~\Big(\frac{p^{-4}}{10q^5k^2}\Big)^{-2}:(5p^2q^3k)^3=\\\\\\=\frac{p^8}{10^{-2}q^{-10}k^{-4}}\cdot\frac{1}{125p^6q^9k^3}=\\\\\\=\frac{100p^2}{125q^{-1}k^{-1}} =\frac{4p^2qk}{5}$