Question

Помогите прошу!(y-4)²,(7x+a)² ,(5c-1)*(5c+1), (3a-2в)*(3a-2в)

Answer 1

${(y - 4)}^{2} = {y}^{2} - 8y + 16 \\ {(7x + a)}^{2} = 49 {a}^{2} + 14xa + {a}^{2} \\ (5c - 1)(5c + 1) = 25 {c}^{2} - 1 \\ (3a - 2b)(3a - 2b) = {(3a - 2b)}^{2} = \\ 9 {a}^{2} - 12ab + 4 {b}^{2}$