Question

а)x^2 -49 = 0 ;
б)3x^2=4x;
найдите корни уравнений

Answer 1

а)+7,-7

б)x=0, x= 4/3

Answer 2

а)
$x {}^{2} - 49 = 0 \\ x {}^{2} = 49 \: \: \: \\ x = \sqrt{49} \: \\ x = 7$ x2=-7
б)
$3x {}^{2} = 4x \\ 3x {}^{2} - 4x = 0 \: \\ x(3x - 4) = 0 \\ x1 = 0 \\ 3x - 4 = 0 \\ x2 = \frac{4}{3}$