Question

Помогите решить уравнение ПОЖАЛУЙСТА!!!!!!!

Answer 1

1. x^2+16x=0
x(x+16)=0
x=0 или x=-16

или sqrt(x) - 2 = 0
sqrt(x)=2
x=4

или x^2+2x-24=0
D=4-4*(-24) = 100
x1=(-2+10)/2 = 4
x2=(-2-10)/2 = -6

2.
$\frac{3 {x}^{2} + 5x }{4} - \frac{7 - 2x}{5} = \frac{3 {x}^{2} + 7}{10} \\ 5(3 {x}^{2} + 5x) - 4(7 - 2x) = 2(3 {x}^{2} + 7) \\ 15 {x}^{2} + 25x - 28 + 8x = 6 {x}^{2} + 14 \\ 9 {x}^{2} + 33x - 42 = 0 \\ 3 {x}^{2} + 11x - 14 = 0$

D = 121-4*3*(-14) = 289
x1 = (-11+17)/6 = 1
x2 = (-11-17)/6 = -28/6 = -14/3