Question

1) Вычислите 10^0.25*40^0,25*5^0,5

2) Вычислите $frac{a^{frac{2}{3}}}{a^{frac{5}{3}}+a^{frac{2}{3}}}$ при а=3

Answer 1

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Answer 2

2)$frac{a^frac{2}{3}}{a^frac{5}{3}+a^frac{2}{3}}=frac{a^frac{2}{3}}{a^frac{2}{3}(a^{frac{5}{3}-frac{2}{3}}+a^{frac{2}{3}-frac{2}{3}})}}=frac{1}{a^frac{3}{3}+a^0}=frac{1}{a+1}$

 

$10^{0.25}*40^{0.25}*5^{0.5}=10^{0.25}*40^{0.25}*25^{0.25}=10000^{0.25}=10$