Question

(5х-3)(х+2)-(х+4)^2=0

Answer 1

(5х-3)(х+2)-(х+4)²=0
5х²+10х-3х-6-(х²+8х+16)=0
5х²+10х-3х-6-х²-8х-16=0
4х²-х-22=0
D=b²-4ac= 353
x₁,₂= $frac{1 +- sqrt{353}}{8}$ 
x₁= $frac{1 +sqrt{353}}{8}$
x₂= $frac{1 - sqrt{353}}{8}$