Предмет: Алгебра, автор: liliakhanipova

log2х+log2(10-х)=4
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Ответы

Автор ответа: sedinalana
0
ОДЗ
{x>0
{10-x>0⇒x<10
x∈(0;10)
log(2)(10x-x²)=4
10x-x²=16
x²-10x+16=0
x1+x2=10 U x1*x2=16
x1=2 U x2=8
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