Question

Решите ур-е:
8x^3-36x^2+54x=27

Answer 1

$(a-b)^3=a^3-3a^2b+3ab^2-b^3== textgreater \ \ 8x^3-36x^2+54x-27=0 \ \ (2x)^3-3*(2x)^2*3+3*(2x)*3^2-3^3=0 \ \ (2x-3)^3=0 \ \ 2x-3=0 \ \ 2x=3 \ \ x=1,5$