Question

y=2(x+2)(x-1)^2 через производную

Answer 1

$y'=2((x+2)'(x-1)^2+(x+2)((x-1)^2)')=\\=2((x-1)^2+2(x+2)(x-1))=\\=2(x-1)(x-1+2x+4)=2(x-1)(3x+3)=6(x^2-1)$