Question

Решить уравнение 5^(4x)+3*5^(4x-2)=140

Answer 1

$5^{4x}+3*5^{4x-2}=140\5^{4x-2}(5^{4x-4x+2}+3)=140\5^{4x-2}(5^2+3)=140\5^{4x-2}*(25+3)=140\5^{4x-2}*28=140\5^{4x-2}=140:28\5^{4x-2}=5^1\4x-2=1\4x=2+1\4x=3\x=3/4\x=0,75$