Question

a^2-16÷2a^2+8a при a=-0,2

Answer 1

$a^{2} -16 \ 2 a^{2} +8a \ = \ (a-4)(a+4) \ 2a(a+4) \ = \ (a-4) \ 2a \ = \( -0.2-4) \ 2*(-0.2) \ = \ -4.2 \ -0.4 \ = \ 10.5$