Question

Помогите решить ,пожалуйста

Answer 1

3ax/(3ax-ax²)=3ax/(ax(3-x))=3/(3-x))

2√13*√2*5*√26=(2*5)√(13*2)*√26=10*√(26)²=10*26=260

[x/(4x-4y)] * [ (x²-y²) /10x²]=[ x/(4(x-y)) ] * [(x-y)(x+y)/10x²]=(x+y)/40x