Question

log3 3-x + log4-x= 1+2 log3 2

Answer 1

log3 3-x + log3 4-x= 1+2 log3 2

log3 3-x + log3 4-x= log3 3+ log3 4

 

(3-x)(4-x)=12

x^2-7x+12-12=0

x^2-7x=0

x(x-7)=0

x=0

x-7=0

x=7