Question

решите пожалуйста 57.18 .Срочно!!!!

Answer 1

$sqrt[3]{x}-sqrt[6]{x}-2>0\ sqrt[6]{x}=t\ t^{2}-t-2>0\ t_{1}+t_{2}=1\ t_{1}t_{2}=-2\ t_{1}=2\ t_{2}=-1\ t in (-infty;-1)cup(2;+infty)\ sqrt[6]{x}=-1 to varnothing\ sqrt[6]{x}=2to x=64\ \ x in (64;+infty)$