Предмет: Алгебра, автор: sargp

Найдите корни уравнения: (х+4)(2х-1)=х(3х+11)

Ответы

Автор ответа: SkyBy
0
(x+4)(2x-1)=x(3x+11)\ 2x^{2}-x+8x-4=3x^{2}+11x\ 2x^{2}+7x-4-3x^{2}-11x=0\ -x^{2}-3x-4=0\ x^{2}+4x+4=0\ (x+2)^{2}=0\ x=-2

Ответ: -2.
Автор ответа: lexusenok
0
2х^2-х+8х-4=3х^2+11х
2х^2+7х-4-3х^2-11х=0
-х^2-4х-4=0
х^2+4х+4=0
D=16-4*1*4=16-16=0
x=-4/2
x=-2
Ответ: -2
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