Question

$1+2log_{(x+2)</var><var>} 5 = log_{5} (x+2)$

Answer 1

$1+2log_{(x+2)} 5 = log_{5} (x+2);\ x+2>0; x+2 neq 1; \ log_{x+2} 5=t neq 0; log_5 (x+2)=frac{1}{t} neq 0;\ 1+2t=frac{1}{t};\ t+2t^2=1;\ 2t^2+t-1=0;\ (2t-1)(t+1)=0;\ t_1=0.5; t_2=-1; t=0.5$

ответ: 0.5