Question

Решите уравнение
В)x²-8=(x-8)(2x+1)
Г)(2x-1)²-1=x(x+2)

Answer 1

в)
х ^2 - 8 = 2x^2 - 16x + x - 8
x^2 - 2x^2 + 16x - x + 8 - 8 = 0
-x^2 + 15x = 0
x^2 - 15x = 0
x ( x - 15) = 0
x1 = 0
x2 = 15

г) (2х - 1)^2 - 1 = x(x + 2)
   4x^2 - 4x + 1 - 1 = x^2 + 2x
  4x^2 - x^2 - 4x - 2x = 0
  3x^2 - 6x = 0
  3x^2 = 6x
    x = 6x : 3x
    x = 2