Предмет: Алгебра, автор: 89261056369

Помогите пожалуйста !!!

Задание №1

Решите уравнение − x^2−10x+4=(x+8)^2.
Задание №2

Решите систему уравнений {4x2−5x=y,
8x−10=y.

Ответы

Автор ответа: 2407Alexa

-x²-10x+4=x²+16x+64
2x²+26x+60=0|:2
x²+13x+30=0
По теореме Вието:
x1+x2=-p=-13
x1*x2=q=30
x1=-3
x2=-10
{4x²-5x=y
{8x-10=y
4x²-5x=8x-10
4x²-5x-8x+10=0
4x²-13x+10=0
D=(-b)²-4ac=(-(-13))²-4*4*10=169-160=9
x1=((-b)+√D)/2*a=(-(-13)+√9)/2*4=16/8=2
x2=((-b)-√D)/2*a=(-(-13)-√9)/2*4=10/8
8x1-10=y1
8*2-10=y1
y1=6
8x2-10=y2
8*(10/8)-10=y2
y2=10-10=0
(2; 6) и (10/8; 0).

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