Question

Решить уравнение
4/(x+2)-3/(x-2)-12/(4-x^2)=1/7

Answer 1

$frac{4}{x+2}- frac{3}{x-2} - frac{12}{4-x^2} = frac{1}{7y} |(4-x^2)=(2-x)(2+x)\ frac{4(2-x)+3(2+x)-12-1(4-x^2)}{4-x^2} =0$
$4(2-x)+3(2+x)-12-1(4-x^2)=0 \ 8-4x+6+3x-12-4+4x^2=0 \ 4x^2-x-2=0 \ D=1+32=33 \ x1= frac{1- sqrt{33} }{8} \ x2= frac{1+ sqrt{33} }{8}$