Предмет: Химия, автор: Вражеская

К 200 г 10%-го раствора соли добавили 30 г соли.Вычислить массовую долю во вновь полученном растворе.

Ответы

Автор ответа: cats086

масса нового раствора = 200+30=230 г
масса соли в изначальном растворе = 200*0,1=20г
масса соли в новом растворе равна 20+30=50г
массовая доля соли в новом растворе = (50/230)*100=21,74%

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