Question

Предварительно сократив дроби выполните сложение 3/12+25/30,10/24+21/54,30/54+22/30,28/40+10/75,12/27+14/21,14/24+15/40,12/18+5/60,4/24+3/36.Помогите дам 30 баллов

Answer 1

$displaystyle frac{3}{12}+ frac{25}{30}= frac{1}{4}+ frac{5}{6}= frac{3+10}{12}= 1frac{1}{12}$

$displaystyle frac{10}{24}+ frac{21}{54}= frac{5}{12}+ frac{7}{18}= frac{15+14}{36}= frac{29}{36}$

$displaystyle frac{30}{54}+ frac{22}{30}= frac{5}{9}+ frac{11}{15}= frac{25+33}{45}= 1frac{13}{45}$

$displaystyle frac{28}{40}+ frac{10}{75}= frac{7}{10}+ frac{2}{15}= frac{21+4}{30}= frac{25}{30}= frac{5}{6}$

$displaystyle frac{12}{27}+frac{14}{21}= frac{4}{9}+ frac{2}{3}= frac{4+6}{9}=1 frac{1}{9}$

$displaystyle frac{14}{24}+ frac{15}{40}= frac{7}{12}+ frac{3}{8}= frac{14+9}{24}= frac{23}{24}$

$displaystyle frac{12}{18}+ frac{5}{60}= frac{2}{3}+ frac{1}{12}= frac{8+1}{12}= frac{9}{12}= frac{3}{4}$

$displaystyle frac{4}{24}+ frac{3}{36}= frac{1}{6}+ frac{1}{13}= frac{13+6}{78}= frac{19}{78}$