Question

Помогите № 3 и 4 ))))))

Answer 1

CxHy + O2 = CO2 + H2O
n(CO2) = n(c) = m/M = 88/44 = 2 моль
n(H2O) = 2n(H) = 2 * m/M = 45/18*2 = 5 моль
n(c):n(H) = 2:5 => C2H5
M(CXHy) = D(H2) * M(H2) = 29*2 = 58 г/моль
M(C2H5) = 29 г/моль
58/29 = 2 => C4H10

CH3-CH=CH-CH2-CH3 + HBr = CH3-CH2-CH(Br)-CH2-CH3