Question

a(a^2-7)-(a+1)(a+2)(a-3)

Answer 1

$a(a^2-7)-(a+1)(a+2)(a-3)=a^3-7a-(a^2+3a+2)(a-3)= a^3-7a-(a^3-3a^2+3a^2-9a+2a-6)= a^3-7a-(a^3-7a-6)=a^3-7a-a^3+7a+6=6$

 

отвте: 6