Question

Решите неравенство,пожалуйста)

Answer 1

$sqrt{frac{x+5}{2x-1}} geq 2; ,; ; ODZ:; left { {{frac{x+5}{2x-1} geq 0} atop {2x-1ne 0}} right. ; ; xin (-infty,-5, ]U(frac{1}{2},+infty)\\frac{x+5}{2x-1} geq 4\\frac{x+5-8x+4}{2x-1} geq 0\\frac{-(7x-9)}{2x-1} geq 0\\frac{7x-9}{2x-1} leq 0\\+++(frac{1}{2})---[, frac{9}{7}, ]+++\\xin (frac{1}{2},frac{9}{7}, ]$