Question

2) (x-1)($x^{2}$ -49) = 0
3)(x-8)($x^{2}$  -9)=0 

Answer 1

$1); ; (x-1)(x^2-49)=0\\(x-1)(x-7)(x+7)=0\\x-1=0; ; ili; ; x-7=0; ; ili; ; x+7=0\\x_1=1,; x_2=7,; x_3=-7\\\2); (x-8)(x^2-9)=0\\(x-8)(x-3)(x+3)=0\\x_1=8,; x_2=3,; x_3=-3$