Question

решите систему уравнений
y-x=2
y^2-2xy-x^2=-28

Answer 1

Решение
y - x = 2
y^2 - 2xy -x ^2 = - 28

y = x + 2
(x+2)^2 -2*x(x+2) -x^2 = - 28
x^2 + 4x + 4 - 2x^2 - 4x - x^2 = - 28
- 2x^2 = - 32
x^2 = 16
x1 = - 4
x2 = 4
y1 = - 4 + 2
y1 = - 2
y2 = 2 + 2
y2 = 4
Ответ: ( - 4; - 2)   (4; 4)