Question

помогите с решением пазязя)

Answer 1

$frac{2x}{x^2-4} - frac{2}{x^2-4}:( frac{x+1}{2x-2}- frac{1}{x-1} ) = frac{2x}{x^2-4} - frac{2}{x^2-4}:( frac{x+1}{2(x-1)}- frac{2}{2(x-1)} ) = \ frac{2x}{x^2-4} - frac{2}{x^2-4}: frac{x+1-2}{2(x-1)} =frac{2x}{x^2-4} - frac{2}{x^2-4}: frac{x-1}{2(x-1)} = \ frac{2x}{x^2-4} - frac{2}{x^2-4}: frac{1}{2} = frac{2x}{x^2-4} - frac{2}{x^2-4}*2 =frac{2x}{x^2-4} - frac{4}{x^2-4} = \ frac{2x-4}{x^2-4} = frac{2(x-2)}{(x-2)(x+2)} = frac{2}{x+2} \ \ x=1/2$
$frac{2}{1/2+2} =2/2.5=20/25=4/5=0.8$