Question

3х(х-2)-(3х-1)(х+4)>8(2-х)

Answer 1

3х^2-6х-(3х^2+12х-х-4)>16-8х

3х^2-6х-3х^2-12х+х+4-16+8х>0

-9х-12>0

-9х>12

х>-1/1:3

Answer 2

$3x(x-2)-(3x-1)(x+4)>8(2-x)\ 3x^2-6x-(3x^2+12x-x-4)>16-8x\ 3x^2-6x-3x^2-12x+x+4>16-8x\ 3x^2-3x^2-6x-12x+x+8x>16-4\ -9x>12\ x>-frac{12}{9}\ x>-frac{4}{3}$