Question

8sinx·cosx=-2корень3

Answer 1

 4·2·sinx·cosx = -2·√3
  4·sin2x =  -2·√3
    sin2x= -2·√3/4 = - √3/2
   2x = (-1)[в степени(k+1)]·π/3+πk
  x = (-1)^(k+1)·π/6+πk