Question

Сравните g(2) и g(-2) если а)g(x)=1/x^2+5; б)g(x)=x/x^2+5; в)g(x)=-x/x^2+5

Answer 1

$a) g(2)=frac1{x^2+5}=frac1{2^2+5}=frac1{4+5}=frac{1}{9}\ g(-2)=frac1{x^2+5}=frac1{(-2)^2+5}=frac{1}{4+5}=frac{1}{9}\ g(2)=g(-2)\ \ b) g(2)=frac{x}{x^2+5}=frac{2}{2^2+5}=frac2{4+5}=frac{2}{9}\ g(-2)=frac{x}{x^2+5}=frac{-2}{(-2)^2+5}=-frac{2}{4+5}=-frac{2}{9}\ g(2)>g(-2)\ \ v)g(2)=-frac{x}{x^2+5}=-frac{2}{2^2+5}=-frac2{4+5}=-frac{2}{9}\ g(-2)=-frac{x}{x^2+5}=-frac{-2}{(-2)^2+5}=frac{2}{4+5}=frac{2}{9}\ g(2)<g(-2)$