Question

Найдите производную функции 
y = 3/x^3 + x^3/3 - 6 корень x

Answer 1

$displaystyle (frac{3}{x^3}+ frac{x^3}{3}-6 sqrt x)'=(frac{3'x^3-3(x^3)'}{(x^3)^2})+ (frac{(x^3)'3-x^3 cdot 3'}{3^2})-$
$displaystyle - (6' sqrt x+6( sqrt x)')= (frac{0-9x^2}{x^6})+( frac{9x^2+0}{9})- (0+ frac{6}{2 sqrt x})=$
$displaystyle = - frac{9}{x^4}+x^2- frac{3 sqrt x}{x}= boxed{frac{x^6-3x^{3,5}-9}{x^4}}$