Question

(6у+2)(5- у)=47-(2у-3)(3у-1)

Answer 1

(6у+2)(5- у)=47-(2у-3)(3у-1)

-6y^2+28y+10=47-6y^2+11y-3

17y=34

y=2

Answer 2

(6y+2)(5-y)=47-(2y-3)(3y-1)

30y-6y(в квадрате)+10-2y=47-6y(в квадрате)+2y+9y-3

28y+10=44+11y

28y-11y=44-10

17y=34

y=2