Question

Дано:ctga=-3; 3/2пи<а<2пи.Вычислите sina,cosa,tga.

Answer 1

1+(ctga)^2=1/(sina)^2 → sina=-1/2
(sina)^2+(cosa)^2=1 → cosa=(3^1/2)/2
tga*ctga=1 → tga=-1/3