Question

Срочно!!!
Разложить на множители.
a^5+a+1
a^3-6a^2-a+30
a^2x(2(x-1)-b^3)+2(2+(b^3-2)x)-b^6
n(n^2-4(a+n)+x(a-n))-a(x-4)(x+4)

Answer 1

$a^3-6a^2-a+30=a^3-3a^2-3a^2+9a-10a+30=\ =left(a^3-3a^2right)-left(3a^2-9aright)-left(10a-30right)=\ =a^2left(a-3right)-3aleft(a-3right)-10left(a-3right)=\ =left(a-3right)left(a^2-3a-10right)=left(a-3right)left(a^2+2a-5a-10right)=\ =left(a-3right)left(left(a^2+2aright)-left(5a+10right)right)=\ =left(a-3right)left(aleft(a+2right)-5left(a+2right)right)=\ =left(a-3right)left(a+2right)left(a-5right).$