Question

Помогите) Сократите дробь
в^2-9/в^2+3в

Answer 1

$frac{b^{2}-9}{b^{2}+3b} = frac{(b-3)(b+3)}{b(b+3)}= frac{b-3}{b}$

Answer 2

(b²-9)/(b²+3b)=(b²-3²)/(b(b+3))=(b-3)(b+3)/(b(b+3))=(b-3)/b