Question

Найти область определения функции
y=(x-2)(x+3)(x-1)/(x+1)(x-2)(x-3)

Answer 1

$y= frac{(x-2)(x+3)(x-1)}{(x+1)(x-2)(x-3)} \ (x+1)(x-2)(x-3) neq 0 \ x+1 neq 0 \ x neq -1 \ x-2 neq 0 \ x neq 2 \ x-3 neq 0 \ x neq 3$

D(y) x∈ $(- infty;-1)U(-1;2)U(2;3)U(3;+infty).$