Question

2sin^2(П/2-x)+корень из 2*cosx=0

Answer 1

2sin²(П/2-x)+√2*cosx=0
2cos²x+√2cosx=0
cosx(2cosx+√2)=0
cosx=0                           2cosx+√2=0
x=π/2+πn, n∈Z             cosx=-√2/2
                                      x=+-3π/4+2πn, n∈Z