Question

уравнения 1) (4/3)^x+1-(4/3)^x=3/16; 2) 9^5x-3=(1/27)^2-3x

Answer 1

$1)( frac{4}{3}) ^{x+1}-( frac{4}{3} )^{x}= frac{3}{16} \ ( frac{4}{3}) ^{x}* frac{4}{3} -( frac{4}{3} )^{x}= frac{3}{16} \ (frac{4}{3}) ^{x}(frac{4}{3} -1)= frac{3}{16} \ (frac{4}{3}) ^{x}frac{1}{3}= frac{3}{16} \ (frac{4}{3}) ^{x}=( frac{4}{3} )^{-2} \ x=-2 \ 2)9^{5x-3}= (frac{1}{27})^{2-3x} \ 3^{10x-6}=3^{9x-6} \ 10x-6=9x-6 \ 10x-9x=-6+6 \ x=0$